Sunday 18 September 2016

StringBuffer object by literal

13.3 literal


Can we create StringBuffer object by literal?
  • It is not possible to create StingBuffer object by using literal
  • Even if we try to create we will get compile time error.
  • So, creating StringBuffer object by using literal means its literally invalid
Invalid Syntax
                     StringBuffer stringBuffer = "Java";  //  Invalid
Thanks for your time.
Nireekshan